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B_{2}H_{6}+NH_{3}\rightarrow A\overset{\Delta }{\rightarrow}B. The product B is

Option: 1

\left ( BN \right )_{x}


Option: 2

2BH_{3}.NH_{3}


Option: 3

\left [ BH_{2}\left ( NH_{3} \right )_{2} \right ]^{+}\left [ BH_{4} \right ]^{-}

 


Option: 4

B_{3}N_{3}H_{6}


Answers (1)

best_answer

Answer (4)

3B_{2}H_{6}+6NH_{3}\rightarrow 3\left [ BH_{2}\left ( NH_{3} \right )_{2} \right ]^{+}\left [ BH_{4} \right ]^{-}\overset{\Delta }{\rightarrow}2B_{3}N_{3}H_{6}+12H_{2}

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