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  • In a common emitter amplifier, using output resistance of  and input resistance of <img alt="2000

In a common emitter amplifier, using output resistance of 5000 \Omega and input resistance of 2000 \Omega, if the peak value of input signal voltage is \mathrm{10 mV \: and \: \beta =50}, then peak value of output voltage is

 

Option: 1

5\times10^{-6}\mathrm{V}


Option: 2

12.50\times10^{-6}\mathrm{V}


Option: 3

1.25\: \mathrm{V}


Option: 4

125.0\: \mathrm{V}


Answers (1)

best_answer

\mathrm{A_v=\frac{\Delta V_0}{\Delta V_i}=\beta \frac{R_0}{R_i} ; \text { So, } \Delta V_0=\Delta V_i \times \beta \frac{R_0}{R_i} }

\mathrm{ \therefore \Delta V_0=10 \times 50 \times \frac{500}{2000}=1250 \mathrm{mV}=1.25 \mathrm{~V}}

Hence option 3 is correct.

 

Posted by

Rishabh

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