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  • In a common emitter configuration of a transistor, the voltage drop across a resistor in the c

In a common emitter configuration of a transistor, the voltage drop across a 500\ \Omega resistor in the collector circuit is \mathrm{0.5\ V} when the collector supply voltage is \mathrm{0.96}, the base current is

Option: 1

\mathrm{\frac{1}{20}mA}


Option: 2

\mathrm{\frac{1}{5}mA}


Option: 3

\mathrm{\frac{1}{20}mA}


Option: 4

\mathrm{\frac{1}{24}mA}


Answers (1)

best_answer

\begin{aligned} & \alpha=0.96 \\ & \beta=\frac{\alpha}{1-\alpha}=\frac{0.96}{1-0.96}=24 \\ & I_C=\frac{V_C}{R}=\frac{0.5}{500}=10^{-3} \mathrm{~A} \\ & I_b=\frac{I_c}{\beta}=\frac{10^{-3}}{24}=\frac{1}{24} \mathrm{~mA} \end{aligned}

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Divya Prakash Singh

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