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  • In a common emitter transistor amplifier, the output resistance is and th

In a common emitter transistor amplifier, the output resistance is 500 \mathrm{k} \Omega and the current gain \mathrm{\beta=49}. If the power gain of the amplifier is \mathrm{5 \times 10^6}, the input resistance is
 

Option: 1

325 \Omega
 


Option: 2

165 \Omega
 


Option: 3

198 \Omega
 


Option: 4

240 \Omega


Answers (1)

best_answer

Given, \mathrm{R_o=500 \mathrm{k} \Omega,\: \beta=49\: and \: P=5 \times 10^6}

We have \mathrm{\quad P=\beta^2 \frac{R_o}{R_i}}

\mathrm{ 5 \times 10^6=\frac{(49)^2 \times 500}{R_i} }

\mathrm{ R_i=\frac{49 \times 49 \times 500}{5 \times 10^6}=240 \Omega }

Hence option 4 is correct.


 

Posted by

Anam Khan

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