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In a mean life of a radioactive sample:
Option: 1
about 1/3 of substance disintegrates

Option: 2
about 2/3 of the substance disintegrates

Option: 3
about 90% of the substance disintegrates

Option: 4
almost all the substance disintegrates.

Answers (1)

best_answer

$\mathrm{t}=\frac{1}{\mathrm{\lambda }} \log \frac{\mathrm{N}_0}{\mathrm{~N}}$

$\text { Given } \mathrm{t}=\tau=\left(\frac{1}{\lambda}\right)$

$\frac{1}{\lambda}=\frac{1}{\lambda} \log \frac{N_0}{N} \Rightarrow \log \frac{N_0}{N}=1$

$\frac{\mathrm{N}_0}{\mathrm{~N}}=2.7 \Rightarrow \mathrm{N}=\frac{\mathrm{N}_0}{2.7}=0.37 \mathrm{~N}_0 \approx \frac{1}{3} \mathrm{~N}_0$

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SANGALDEEP SINGH

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