Get Answers to all your Questions

header-bg qa

In a parallel LCR circuit shown in the Fig. at resonance

Option: 1

the source current is maximum


Option: 2

the impedance of the circuit is minimum and is equal to R


Option: 3

the resonance frequency will be the same as for a series resonance circuit with the same value of L, C and R


Option: 4

the voltage across L and C are in phase.


Answers (1)

best_answer

In a parallel resonance circuit, at resonance

\mathrm{\omega=\frac{1}{\sqrt{L C}} \sqrt{\frac{L / C-R_L^2}{L / C-R_C^2}}}

for a good qual;ity capacitor Rc = 0 and we put RL = R. Then

\mathrm{\omega=\sqrt{\frac{1}{L C}-\frac{R^2}{L^2}}}

If resistance is neglected then the condition of resonance in both series and parallel circuit become the same, namely \mathrm{\omega=(L C)^{-1 / 2}}

Posted by

vishal kumar

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks