Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Medical
  • In a photoelectric effect experiment, for radiation with frequency with <img alt="h v_0=8 \mathrm{e}V" src="/latex-image/

In a photoelectric effect experiment, for radiation with frequency v_0 with h v_0=8 \mathrm{e}V, electrons are emitted with energy 2 \mathrm{e}V. What is the energy of the electrons emitted for incoming radiation of frequency 1.25 \nu_0?
 

Option: 1

1 \mathrm{eV}


Option: 2

3.25 \mathrm{eV}


Option: 3

4 \mathrm{eV}


Option: 4

9.25 \mathrm{eV}


Answers (1)

best_answer


\mathrm{h} \nu=\mathrm{W}_{\mathrm{ex}}+\text{maximum kinetic energy } \\ \mathrm{h}\nu_0=8 \mathrm{eV}=\mathrm{W}_{\mathrm{ex}}+2 \mathrm{eV} \Rightarrow \mathrm{W}_{\mathrm{ex}}=6 \mathrm{eV}

For incoming radiation, energy is \mathrm{h} \times 1.25 \mathrm{\nu}_0=10 \mathrm{eV}, \mathrm{W}_{\mathrm{ex}}=6 \mathrm{eV}
therefore Kinetic energy (maximum) = 4 \mathrm{eV}

Posted by

Rakesh

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

Before NEET, CMC Vellore’s unique MBBS admissions tested aptitude along with merit; paper-leak restarts debate
anam-khan

NEET-UG paper leak fallout: Latur admin orders crackdown on illegal coaching classes
anam-khan

Re-NEET in 30 days a ‘massive logistical challenge’, NTA adopts ‘zero trust’ policy: Report

Latest Question