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  • In a plane electromagnetic wave travelling in free space, the electric field component oscillates sinusoidally at a frequency of <img alt="2.0 \times 10^{10}" src="https://entrancecorner.oncodecogs

In a plane electromagnetic wave travelling in free space, the electric field component oscillates sinusoidally at a frequency of 2.0 \times 10^{10} Hz and amplitude 48 \, V m^{-1}. Then the amplitude of oscillating magnetic field is : \text { (Speed of light in free space }=3 \times 10^8 \mathrm{~m} \mathrm{~s}^{-1} \text { ) }

Option: 1

1.6 \times 10^{-9} \mathrm{~T}


Option: 2

1.6 \times 10^{-8} \mathrm{~T}


Option: 3

1.6 \times 10^{-7} \mathrm{~T}


Option: 4

1.6 \times 10^{-6} \mathrm{~T}


Answers (1)

best_answer

\begin{aligned} & \because C=\frac{E_0}{B_0} \\ & \Rightarrow \quad B_0=\frac{E_0}{C}=\frac{48}{3 \times 10^8}=16 \times 10^{-8}=1.6 \times 10^{-7} \mathrm{~T} \end{aligned}

Posted by

Ritika Kankaria

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