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  • In a reverse biased diode when the applied voltage changes by , the current is found to change by <i

In a reverse biased diode when the applied voltage changes by \mathrm{1V}, the current is found to change by \mathrm{0.5\ \mu A}. The reverse bias resistance of the diode is

Option: 1

2 \times 10 ^{5} \Omega


Option: 2

2 \times 10^{6} \Omega


Option: 3

200 \Omega


Option: 4

2 \Omega


Answers (1)

best_answer

Reverse resistance \mathrm{=\frac{\Delta V}{\Delta I}=\frac{1}{0.5 \times 10^{-6}}=2 \times 10^6 \Omega}

Posted by

Gaurav

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