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  • In a sceond order reaction 40% of a substance is dissociated in 80 min. The time teken by 60 % of its dissociation is   Option: 1

In a sceond order reaction 40% of a substance is dissociated in 80 min. The time teken by 60 % of its dissociation is 
 

Option: 1

180 min


Option: 2

100 min
 


Option: 3

150 min


Option: 4

200 min


Answers (1)

best_answer

For second order reaction 

\mathrm{K t=\frac{1}{[A]}-\frac{1}{ [A]_0}=\frac{x}{A_0\left[A_0-x \mid\right.}}

If \mathrm{x=40 \% \quad(a-x)=60 \% \quad a=100 \%}

\begin{aligned} 80 \times \text{k} & =\frac{40}{100(60)}=\frac{1}{150} \\ \text{k} & =\frac{1}{80 \times 150} \end{aligned}

When \mathrm{x=60 \%,(a-x)=40 \%}

\mathrm{k=\frac{1}{t} \times \frac{\omega x}{100(40)}=\frac{1}{t} \times \frac{60}{100 \times 40}}

\mathrm{t=\frac{1}{k} \times \frac{60}{100 \times 40}=\frac{150}{1} \times 80 \times \frac{60}{100 \times 40}}

\mathrm{t=\frac{15 \times 8 \times 6}{4}=180 \mathrm{~min} .}

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Rishi

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