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  • In a zero order reaction for every rise of temperature, the rate is d

In a zero order reaction for every 10^{\circ} \mathrm{C} rise of temperature, the rate is doubled. If the temperature is increased from 10^{\circ} \mathrm{C} to 110^{\circ} \mathrm{C}, rate of reaction will becomes:
 

Option: 1

1024 times
 


Option: 2

512 times


Option: 3

64 times


Option: 4

128 times


Answers (1)

best_answer

\begin{aligned} \therefore \quad \frac{r_{110} c}{r_{10} c} & =(2)^{\left\{\frac{110-10}{10}\right\}} \\ \\\: \: \: \: \: \: \: \: \: \: \: \: \; \; \; \; = (2)^{10} \\\\\frac{r_{110} \cdot c}{r_{10} \cdot c} & =1024 \text { times } \end{aligned}

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Pankaj Sanodiya

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