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In a Zeroth order reaction, for every \mathrm{10^{\circ} \mathrm{C}} rise of temperature, the rate is doubled. It the kmp. is increased from \mathrm{30^{\circ} \mathrm{C}\, \, to \, \, 130^{\circ} \mathrm{C}, } the rate of the reaction will become

Option: 1

20 times


Option: 2

1028 times


Option: 3

512 times


Option: 4

128 times


Answers (1)

best_answer

Each \mathrm{10^{\circ} \mathrm{C}}, rate doubles

So for \mathrm{100^{\circ} \mathrm{C}=10 \times 10^{\circ} \mathrm{C}}

     \mathrm{ \text { Rate becomes }=(2)^{10}=1028 }

Posted by

Devendra Khairwa

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