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  • In an ac circuit V and I are given by <img alt="\mathrm{\begin{aligned} & V=150 \sin (150 t) V \text { and } \\ & I=150 \sin \left(150 t+\frac{\pi}{3}\right) A \end{aligned}}" src

In an ac circuit V and I are given by

\mathrm{\begin{aligned} & V=150 \sin (150 t) V \text { and } \\ & I=150 \sin \left(150 t+\frac{\pi}{3}\right) A \end{aligned}}

The power dissipated in the circuit is

Option: 1

5625 W


Option: 2

4825 W


Option: 3

7450 W


Option: 4

3425 W


Answers (1)

best_answer

\mathrm{E_0=150 \mathrm{~V} \text { and } \mathrm{I}_0=150 \times 10^{-3} \mathrm{~mA} \text { and } \phi=60^{\circ}}

\mathrm{\therefore \quad P=\frac{E_0}{\sqrt{2}} x \frac{I_0}{\sqrt{2}} \cos \varphi=\frac{150 \times 150}{2} x \frac{1}{2}=5625 \mathrm{watt}}

Posted by

Suraj Bhandari

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