Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Medical
  • In an adsorption isotherm, the intercept is 2.5 and the angle made by the isotherm is . At 20 bar pr

In an adsorption isotherm, the intercept is 2.5 and the angle made by the isotherm is 45^{\circ}. At 20 bar pressure, how much gas is adsorbed on 10 \mathrm{~g} of active metal surface?

Option: 1

50 \mathrm{~g}

 


Option: 2

250 \mathrm{~g}
 


Option: 3

300 \mathrm{~g}
 


Option: 4

500 \mathrm{~g}


Answers (1)

best_answer

According to the formula, \mathrm{x / m=k p^{1 / n}\textrm{ or }\log x / m=\log k+1 / n \log p}

Applying this formula on \mathrm{y=m x+C} makes \mathrm{1 / n} the slope. The given angle is \mathrm{45^{\circ} and \tan 45^{\circ}=1}. So,\mathrm{ 1 / n=1\: and\: k=2.5 \: and\: p=20} bar is given.

Putting these values in the formula.

\mathrm{ x / m=2.5 \times 20^1=2.5 \times 20=50 }

\mathrm{ x=50 \times 10=500 \mathrm{~g} }

Hence option 4 is correct.

Posted by

qnaprep

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

NEET 2026: Odisha aspirant dies by suicide fearing failure
anam-khan

NEET 2026 Answer Key (Out) LIVE: Challenge window link at neet.nta.nic.in soon; result date, cutoff
anam-khan

NEET UG Answer Key 2026 (OUT) LIVE: NTA provisional keys out neet.nta.ac.in; challenge window opens soon

Latest Question