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  • In an ammeter 0.2% of main current passes through the galvanometer. If resistance of galvanometer is G, the resistance of ammeter will be:Option: 1 <

In an ammeter 0.2% of main current passes through the galvanometer. If resistance of galvanometer is G, the resistance of ammeter will be:

Option: 1

\frac{1}{499}\text{G}


Option: 2

\frac{499}{500}\text{G}


Option: 3

\frac{1}{500}\text{G}


Option: 4

\frac{500}{499}\text{G}


Answers (1)

best_answer

As we discussed in

I_{G}=0.2 \%\:of\:I\:\:\:=\frac{0.2}{100}I\:=\:\frac{1}{500}I

Current through the shunt

I_{S}=I-I_{G}=I-\frac{I}{500}=\frac{499}{500}\:I

I_{G}S=I_{S}S\:\:\:=>\:\frac{I}{500}G=\frac{499}{500}S\:\:\:\:\:S=\frac{G}{499}

Resistance of ammeter RA is

\frac{1}{R_{A}}=\frac{1}{G}+\frac{1}{S}\:\:\:\:\: = \frac{1}{G}+\frac{499}{G}=\frac{500}{G}

\therefore B_{A} = \frac{G}{500}

Posted by

Riya

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