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  • In an electron gun, the potential difference between the filament and plate is . What

In an electron gun, the potential difference between the filament and plate is 3000 \mathrm{~V}. What will be the velocity of electron emitting from the gun?


 

Option: 1

3 \times 10^8 \mathrm{~m} / \mathrm{s}


Option: 2

3.18 \times 10^7 \mathrm{~m} / \mathrm{s}


Option: 3

3.52 \times 10^7 \mathrm{~m} / \mathrm{s}


Option: 4

3.26 \times 10^7 \mathrm{~m} / \mathrm{s}


Answers (2)

best_answer

\begin{aligned} &\mathrm{V}=3000 \text { volt }\\ & \frac{1}{2} \mathrm{mv}^2=\mathrm{eV} \Rightarrow \mathrm{v}=\sqrt{\frac{2 \mathrm{eV}}{\mathrm{m}}} \\ & \therefore \quad \mathrm{v}=\sqrt{\frac{2 \times 1.6 \times 10^{-19} \times 3000}{9.1 \times 10^{-31}}}=32.6 \times 10^6=3.26 \times 10^7 \mathrm{~m} / \mathrm{s} \end{aligned}

Posted by

Sayak

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3.26×107

 

Posted by

Guru G

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