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Screenshot_2019-01-23_at_4.55.28_PM.png In an experiment it showed that 10 ml of 0.05M solution of chloride required 10 mL of 0.1 M solution of AgNO3 , which of the following will be the formula of the chloride (X stands for the symbol of the element other than chlorine):

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Stoichiometry - Stoichiometry deals with measurements of reactants and products in a chemical reaction. aA (g) + bB (g) → cC (g) + dD (g) Here, ‘a’ moles of A(g) reacts with ‘b’ moles of B(g) to give ‘c’ mole of C(g) and ‘d’ moles of D(g)  No. of moles of AgNO3=10-3 mol No. of moles the chloride= 0.5 x 10-3 mol Suppose the formula for the chloride is XCln then moles of chloride ion=n x 0.5 x 10-3 The reaction goes as follows: Ag+ + Cl- = AgCl Then, going by stoichiometry we get n x 0.5 x 10-3= 10-3 n=2 Therefore, the formula is XCl2( answer)
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Stoichiometry -

Stoichiometry deals with measurements of reactants and products in a chemical reaction.

- wherein

aA (g) + bB (g) → cC (g) + dD (g)

Here, ‘a’ moles of A(g) reacts with ‘b’ moles of B(g) to give ‘c’ mole of C(g) and ‘d’ moles of D(g)

 

 No. of moles of AgNO3=10-3 mol

No. of moles the chloride= 0.5 x 10-3 mol

Suppose the formula for the chloride is XCln then moles of chloride ion=n x 0.5 x 10-3

Reaction goes as follows:

Ag^{+} \: +\: \: Cl^{-} \: \: \rightarrow AgCl

Then, going by stoichiometry we get

n x 0.5 x 10-3= 10-3

\Rightarrow n=2

Therefore, formula is XCl2

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Ankit

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