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  • In an experiment to measure the internal resistance of a cell by a potentiometer, it is found that the balance point is at a length of 2 m when the cell is shunted by a 5 <img alt="\Omega" src="htt

In an experiment to measure the internal resistance of a cell by a potentiometer, it is found that the balance point is at a length of 2 m when the cell is shunted by a 5 \Omega resistance and is at a length of 3 m when the cell is shunted by a 10 \Omega resistance, the internal resistance of the cell is when

Option: 1

1.5 \Omega


Option: 2

10 \Omega


Option: 3

15\Omega


Option: 4

1 \Omega


Answers (1)

best_answer

In case of internal resistance measurement by potentiometer,
\mathrm{\frac{V_1}{V_2}=\frac{l_1}{l_2}=\frac{\left[E R_1 /\left(R_1+r\right)\right]}{\left[E R_2 /\left(R_2+r\right)\right]}=\frac{R_1\left(R_2+r\right)}{R_2\left(R_1+r\right)} }
Here \mathrm{l_1=2 \mathrm{~m}, l_2=3 \mathrm{~m}, R_1=5 \Omega~ and~ R_2=10 \Omega}

\mathrm{\therefore \frac{2}{3}=\frac{5(10+r)}{10(5+r)} ~or~ r=10 \Omega}

Posted by

jitender.kumar

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