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In given circuit, the heat produced in $2\Omega$ resistor due to current flowing through its $8$ calories per secound.

The heat generated in $3\Omega$ resistor is -
Option: 1
$4$ calories

Option: 2
$3$ calories

Option: 3
$8$ calories

Option: 4
$16$ calories

Answers (1)

best_answer

$R_{A B}=2 R_{C D} .$ Hence current in $AB$ is half of that of $CD.$

$P_3\rightarrow$ Heat dissipation in $3\Omega$ resistor.

$P_2\rightarrow$ Heat dissipation in $2\Omega$ resistor.

$\frac{P_3}{P_2}=\frac{(i / 2)^2 R_3}{i^2 R_2}=\frac{i^2 \times 3}{4 \times i^2 \times 2}=\frac{3}{8}$

$\begin{aligned} P_3=\frac{3}{8} \times P_2 & =\frac{3}{8} \times 8 \text { calories } \\ P_3 & =3 \text { calories } \end{aligned}$

Posted by

vishal kumar

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