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In presence of interspace charge, at plate voltage of \mathrm{200\ V}, the current is \mathrm{80\ mA}. Then the current in mA at \mathrm{400\ V} will be

Option: 1

160 \sqrt{2}


Option: 2

2 \sqrt{2}


Option: 3

80 / \sqrt{2}


Option: 4

None of these 


Answers (1)

best_answer

\mathrm{\begin{aligned} & \frac{I_2}{I_1}=\left(\frac{V_2}{V_1}\right)^{3 / 2} \text { or } I_2=I_1\left(\frac{V_2}{V_2}\right)^{3 / 2} \\ & =80\left(\frac{400}{200}\right)^{3 / 2}=80 \times 2 \sqrt{2}=160 \sqrt{2} \end{aligned}}

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Pankaj

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