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  • In steady state with steady current, the potential drop across capacitor is: <img alt="" src="https://cdn.entrance360.com/media/uploads/2023/08/21/i10.png" style="height:258px; width:322p

In steady state with steady current, the potential drop across capacitor is:

Option: 1

4V/3


Option: 2

V/3


Option: 3

2V/3


Option: 4

V


Answers (1)

best_answer

No current in steady state in capacitor: let current be I, apply Kirchoff's voltage law in A BCDEFA loop.
\begin{aligned} & 2 V-I(2 R)-I R-V=0 \\ & V=2 I R+I R \Rightarrow I=\frac{V}{3 R} . \end{aligned}

Applying Kirchoff law in the ABCFA.
\begin{aligned} & 2 V-2 R \times \frac{V}{3 R}-V_{\text {cap }}-V=0 \\ & V-\frac{2 V}{3}=V_{\text {cap }} \Rightarrow V_{\text {cap }}=V / 3 \end{aligned}

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chirag

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