Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa

In the circuit shown in Fig. \mathrm{E_1=E_2=E_3=2 \mathrm{~V} } and \mathrm{R_1=R_2=4 \Omega}. The current flowing between points A and B through battery \mathrm{E_2} is
 

Option: 1

 Zero
 


Option: 2

2 A from A to B
 


Option: 3

 2 A from B to A
 


Option: 4

 None of the above


Answers (1)

best_answer

For loop (1), 2+2-4 I_1=0 \Rightarrow\mathrm{ I_1-1} \mathrm{~A}


For loop (2), \mathrm{ -2-2+4 I_2=0 \Rightarrow I_2=1} \mathrm{~A}
So, the current from A to B is \mathrm{I_1+I_2=2 \mathrm{~A}}

Posted by

chirag

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

NEET UG Paper Leak 2026 LIVE: NTA response sheet soon at neet.nta.nic.in; RSOG investigation on paper leak
anam-khan

NEET UG 2026 irregularities under investigation; NTA says full cooperation being extended to agencies
anam-khan

NEET UG 2026 Tie-Breaking Rule Explained: Here’s how ranks are decided

Latest Question