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In the circuit shown in Fig. \mathrm{E_1=E_2=E_3=2 \mathrm{~V} } and \mathrm{R_1=R_2=4 \Omega}. The current flowing between points A and B through battery \mathrm{E_2} is
 

Option: 1

 Zero
 


Option: 2

2 A from A to B
 


Option: 3

 2 A from B to A
 


Option: 4

 None of the above


Answers (1)

best_answer

For loop (1), 2+2-4 I_1=0 \Rightarrow\mathrm{ I_1-1} \mathrm{~A}


For loop (2), \mathrm{ -2-2+4 I_2=0 \Rightarrow I_2=1} \mathrm{~A}
So, the current from A to B is \mathrm{I_1+I_2=2 \mathrm{~A}}

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