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  • In the circuit shown in Fig. switch S is closed at time t=0, Let   and <img alt="\mathrm

In the circuit shown in Fig. switch S is closed at time t=0, Let \mathrm{I_1}  and \mathrm{I_2}  be the currents at any finite time t, then the ratio \mathrm{\frac{I_1 }{I_2}}
 

Option: 1

 Is constant
 


Option: 2

 Increases with time


Option: 3

 Decreases with time


Option: 4

 First increases, then decreases


Answers (1)

best_answer

Here, \mathrm{I_1=\frac{V}{R} e^{-t / R C}, I_2=\frac{V}{R} e^{-t / 2 R C} }

\mathrm{\therefore \frac{I_1}{I_2}=e^{-t / 2 R C+t / 2 R C}=e^{-t / 2 R C}=\frac{1}{e^{t / 2 R C}} }

From this expression, it is clear that when t increases, ratio decreases

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Shailly goel

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