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In the context of an irregular mating population, characterized by the presence of an autosomal recessive lethal gene with a frequency of 0.4, what would be the estimated frequency of carriers among a population consisting of 200 individuals?

Option: 1

96


Option: 2

36


Option: 3

104


Option: 4

72


Answers (1)

best_answer

In Hardy-Weinberg equilibrium, 

p = frequency of the dominant allele

q = frequency of the recessive allele

In the question it is given that, q = 0.4

Applying Hardy-Weinberg equilibrium

p + q = 1

p = 1- 0.4 = 0.6 

Hence, the estimated frequency of carriers =  2pq = 2 x 0.4 x 0.6 = 0.48

Therefore, the estimated frequency of carriers in a population of 200 individuals with an autosomal recessive lethal gene frequency of 0.4 is: 0.48 x 200  = 96

Hence, the correct answer is option 1. 

Posted by

Ritika Harsh

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