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  • In the experiment, calculate the acceleration due to gravity, By using simple pendulum, which have time period of 0.3 second is measured from time of 50 oscillation with a watch of one second resol

In the experiment, calculate the acceleration due to gravity, By using simple pendulum, which have time period of 0.3 second is measured from time of 50 oscillation with a watch of one second resolution. When length is 5 cm known to 1 mm accuracy find accuracy in the 'g'

Option: 1

15.33 %


Option: 2

12.33 %


Option: 3

13 %


Option: 4

15.55 %


Answers (1)

best_answer

\begin{aligned} & T=2 \pi \sqrt{\frac{l}{g}} \\ & g=\frac{1}{4 \pi^2 l} \frac{T^2}{l}\Rightarrow \frac{\Delta g}{T}= \frac{2 \Delta T}{T}+\frac{\Delta l}{l} \\ & \frac{\Delta g}{g}=2 \times \frac{1}{50 \times 0.3}+\frac{1 \mathrm{~mm}}{5 \mathrm{~cm}} \\ & =0.1533 \\ & \frac{\Delta g}{g} \times 100=15.33 \% . \end{aligned}

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Kshitij

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