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In the given figure, three blocks are connected by masses cords. Masses of the block are $\mathrm{m, 3 m}$ and $\mathrm{5 m}$ and they are pulled by a force $\mathrm{F}$ on a frictionless horizontal surface. If the tension $\mathrm{T_1=16 \mathrm{~N}$ then $\mathrm{ T_2}$ is equal to

Option: 1
$\mathrm{6N}$

Option: 2
$\mathrm{10 N}$

Option: 3
$\frac{80}{3N}$

Option: 4
$\mathrm{18N}$

Answers (1)

best_answer

$\mathrm{F-T_1=m a, T_1-T_2=3 m a, F-T_2=4 m a}$

Given, $\mathrm{T_1=16 \mathrm{~N}, T_2= ? }$

$F =9 m a \\$
$9 m a-16 =m a \\ m a =2 \mathrm{~N}, \therefore F=18 \mathrm{~N} \\$
$\mathrm{\therefore T_2=10 \mathrm{~N} -8 \mathrm{~N}}$

$=10 \mathrm{~N}$

Posted by

manish painkra

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