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  • In the given nuclear reaction, the element is :  <img alt="{ }_{11}^{22} N a \rightarrow X+e^{+}+v" src="https://entrancecorn

In the given nuclear reaction, the element \mathrm{X} is :  { }_{11}^{22} N a \rightarrow X+e^{+}+v

Option: 1

\mathrm{^{23}_{10}Ne}


Option: 2

\mathrm{^{22}_{10}Ne}


Option: 3

\mathrm{^{22}_{12}Mg}


Option: 4

\mathrm{^{23}_{11}Na}


Answers (1)

{ }_{11}^{22} Na \rightarrow { }_{z}^{A} X+^{0}_{1} e+v

\mathrm{22 =A+0} \\

\mathrm{\therefore A=22} \\

\mathrm{11 =Z+1} \\

\mathrm{\therefore Z =10}

The atomic number and atomic mass number of X are 10 and 22 respectively

\mathrm{\therefore X={ }_{10}^{22} \mathrm{Ne}}

Hence the correct option is 2

Posted by

Kshitij

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