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  • In the region between the plane   and  <img alt="\mathrm{\mathrm{z}=\mathrm{a}(\m

In the region between the plane \mathrm{z}=0  and  \mathrm{\mathrm{z}=\mathrm{a}(\mathrm{a}>0)} , the uniform electric and magnetic fields are given by \mathrm{\overrightarrow{E}=E_0(\hat{k}-\hat{j}), \vec{B}=B_0 \hat{i}} . If a positive point charge q is projected from the origin with velocity \mathrm{v_0 \hat{k}} , then the value of \mathrm{E_0}such that the particle moves undeviated upto the plane z=a, is

Option: 1

\frac{\mathrm{v}_0 \mathrm{~B}_0}{\sqrt{2}}


Option: 2

\mathrm{V}_0 \mathrm{~B}_0


Option: 3

\mathrm{V}_0 \mathrm{~B}_0 \sqrt{2}


Option: 4

\mathrm{\frac{v_0 B_0}{2}}


Answers (1)

best_answer

Cross field     \mathrm{E_0=V_0 B_0}

Posted by

Suraj Bhandari

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