Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Medical
  • Length of a solenoid is 60 cm and its total number of turns is 1250. If 2A current is passed through it, what will be the magnetic field at any point on its axis

Length of a solenoid is 60 cm and its total number of turns is 1250. If 2A current is passed through it, what will be the magnetic field at any point on its axis

Option: 1

5.23\times 10^{-3}wb/m^2


Option: 2

6.23\times 10^{-3}wb/m^2


Option: 3

2.03\times 10^{-3}wb/m^2


Option: 4

None


Answers (1)

best_answer

Number of turns =1250, length =60 cm =0.6m 

\therefore Number of turns per unit length, n=\frac{1250}{0.6}m^{-1}

So, the magnetic field at any point on its axis, 

B=\mu_0 nI

=4\pi \times 10^{-7}\times\frac{1250}{0.6}\times2

=5.23\times 10^{-3}wb/m^2

Posted by

avinash.dongre

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

NEET UG 2026 leak probe traces guess paper trail from Kerala student to Rajasthan network
anam-khan

'Replace NTA': FAIMA files plea in SC over NEET UG 2026 paper leak
anam-khan

NEET UG 2026 Paper Leak LIVE: Protests erupt across states, paper leak probe expands; re-NEET date soon

Latest Question