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Let p and E denote the linear momentum and energy respectively of a photon. If the wavelength is decreased -

Option: 1

both p and E increase


Option: 2

p increases and E decreases


Option: 3

p decreases and E increases


Option: 4

both p and E decreases


Answers (1)

best_answer

\begin{aligned} & \mathrm{p}=\frac{\mathrm{E}}{\mathrm{c}}=\frac{\mathrm{h} v}{\mathrm{c}}=\frac{\mathrm{h}}{\lambda} \\ & \therefore \lambda \downarrow \Rightarrow \mathrm{p} \uparrow \\ & \mathrm{E}=\mathrm{h} v=\frac{\mathrm{hc}}{\lambda} \\ & \therefore \lambda \downarrow \Rightarrow \mathrm{E} \uparrow \end{aligned}

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seema garhwal

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