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  • let T be the mean life of a radioactive sample, 15 % of the active nuclei present in the sample initially will decay in time-  Option: 1

let T be the mean life of a radioactive sample, 15 % of the active nuclei present in the sample initially will decay in time-
 

Option: 1

\mathrm{ 2 T }


Option: 2

\mathrm{\frac{T \ln_2}{2} }


Option: 3

\mathrm{4 T }


Option: 4

\mathrm{2 T \ln_2}


Answers (1)

best_answer

when 75% decays, 25% left undecayed

This requires a time \mathrm{t=2 t_{1 / 2}=2 \frac{\ln 2}{\lambda}}

As \frac{1}{\lambda} =\mathrm{T}

\mathrm{t =2 T \ln_2 }

Posted by

Deependra Verma

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