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Light of wavelength 400 nm is incident continuously on a cesium ball (work function 1.9eV) The maximum potential to which the ball will be charged is-

Option: 1

3.1 V


Option: 2

1. 2 V


Option: 3

Zero


Option: 4

Infinite


Answers (1)

best_answer

\begin{aligned} & \mathrm{eV}_{\mathrm{s}}=\frac{12400}{4000}-1.9=3.1-1.9 \\ & \mathrm{eV}_{\mathrm{s}}=1.2 \mathrm{eV} \\ & \mathrm{V}_{\mathrm{s}}=1.2 \mathrm{~V} \end{aligned}

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