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Light of wavelength 3500 \AA is incident on two metals A and B,A of work function 4.2 eV and B of work function 1.19 eV respectively. The photoelectrons will be emitted by -

Option: 1

metal A
 


Option: 2

metal B


Option: 3

both A and B


Option: 4

neither metal A nor metal B


Answers (1)

best_answer

E= \frac{12420}{3500}=3.54 \ eV
So electron will be emitted only from B .

Posted by

Kuldeep Maurya

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