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Light of wavelength \lambda strikes a photo-sensitive surface and electrons are ejected with kinetic energy E . If the kinetic energy is to be increased to 2E , the wavelength must be changed to \lambda'  where -

Option: 1

\lambda '= \frac{\lambda}{2}


Option: 2

\lambda'= 2\lambda


Option: 3

\frac{\lambda}{2}< \lambda'< \lambda


Option: 4

\lambda'> \lambda


Answers (1)

best_answer

\text { If } \lambda^{\prime}=\lambda / 2 \quad \Rightarrow E_2>2 E_1
But here \mathrm{E}_2=2 \mathrm{E}_1 \quad \text { So } \lambda^{\prime}>\lambda / 2
So answer is 

Posted by

mansi

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