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List -I (Oxoaciids of Sulphur) List - II

 (Bonds of Sulphur)

A.  Peroxodisulphuric acid I. \text { Two } \mathrm{S}-\mathrm{OH} \text {, Four } \mathrm{S}=\mathrm{O} \text {, One } \mathrm{S}-\mathrm{O}-\mathrm{S}
B. Sulphuric acid II. \text { Two } \mathrm{S}-\mathrm{OH} \text {, One } \mathrm{S}=\mathrm{O}
C. Pyrosulphuric acid III. \text { Two } \mathrm{S}-\mathrm{OH} \text {, Four } \mathrm{S}=\mathrm{O} \text {, One } \mathrm{S}-\mathrm{O}-\mathrm{O}-\mathrm{S}
D.  Sulphurous acid IV. \text { Two } \mathrm{S}-\mathrm{OH} \text {, Two } \mathrm{S}=\mathrm{O}

 Choose the correct answer from the options given below:

 

Option: 1

A-I, B-III, C-II, D-IV


Option: 2

A-III, B-IV, C-I, D-II


Option: 3

A-I, B-III, C-IV, D-II


Option: 4

A-III, B-IV, C-II, D-I


Answers (1)

best_answer

A. Peroxodisulphuric acid : 

\text {III. Two } \mathrm{S}-\mathrm{OH} \text {, Four } \mathrm{S}=\mathrm{O} \text {, One } \mathrm{S}-\mathrm{O}-\mathrm{O}-\mathrm{S}
B. Sulphuric acid :

\text {IV. Two } \mathrm{S}-\mathrm{OH} \text {, Two } \mathrm{S}=\mathrm{O}
C. Pyrosulphuric acid :

\text {II. Two } \mathrm{S}-\mathrm{OH} \text {, One } \mathrm{S}=\mathrm{O}
D. Sulphurous acid : \text {I. Two } \mathrm{S}-\mathrm{OH} \text {, Four } \mathrm{S}=\mathrm{O} \text {, One } \mathrm{S}-\mathrm{O}-\mathrm{S}

\text { (2) A-III, B-IV, C-I, D-II } is correct.

Posted by

jitender.kumar

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