Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Medical
  • Magnetic field intensity at the centre of a coil of 50 turns, radius 0.5 m and carrying a current of 2 A isOption: 1 <img alt="0.5 \times 10^{-5} \ma

Magnetic field intensity at the centre of a coil of 50 turns, radius 0.5 m and carrying a current of 2 A is

Option: 1

0.5 \times 10^{-5} \mathrm{~T}


Option: 2

1.25 \times 10^{-4} \mathrm{~T}


Option: 3

3 \times 10^{-5} \mathrm{~T}


Option: 4

4 \times 10^{-5} \mathrm{~T}


Answers (1)

best_answer

We know that magnetic field at the centre of circular coil,
B=\frac{\mu_0 \mathrm{In}}{2 \mathrm{r}}=\frac{4 \pi \times 10^{-7} \times 2 \times 50}{2 \times 0.5}=1.25 \times 10^{-4} \mathrm{~N}
 

Posted by

Rishi

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

NEET UG 2026 irregularities under investigation; NTA says full cooperation being extended to agencies
anam-khan

NEET UG 2026 Tie-Breaking Rule Explained: Here’s how ranks are decided
anam-khan

NEET 2026: Odisha aspirant dies by suicide fearing failure

Latest Question