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Match List - I with List - II

List - I List - II
(a)     [Fe(CN)_{6}]^{3-} (i) 5.92 BM

(b)    [Fe(H_{2}O)_{6}]^{3+}

 (ii) 0 BM
(c)    [Fe(CN)_{6}]^{4-} (iii) 4.90 BM
(d)    [Fe(H_{2}O)_{6}]^{2+} (iv) 1.73 BM

Choose the correct options from the given below:
 

Option: 1

(a) - (iv), (b) - (ii), (c)- (i), (d)- (iii)


Option: 2

(a) - (ii), (b) - (iv), (c)- (iii), (d)- (i)


Option: 3

(a) - (i), (b) - (iii), (c)- (iv), (d)- (ii)

 


Option: 4

(a) - (iv), (b) - (i), (c)- (ii), (d)- (iii)


Answers (1)

best_answer

CN^- is a strong field ligand and will cause pairing while H_2O is a weak field ligand and will not cause pairing

Thus, Fe^{3+} which has d^5 configuration and will have 1 unpaired electron in the complex with CN^- and 5 unpaired electrons in the complex with H_2O

And, Fe^{2+} which has d^6 configuration and will have 0 unpaired electron in the complex with CN^- and 4 unpaired electrons in the complex with H_2O

Complex unpaired electrons (n) Magnetic moment (BM)

[Fe(CN)_{6}]^{3-}

1

 1.73

[Fe(H_{2}O)_{6}]^{3+}

 5 5.92

[Fe(CN)_{6}]^{4-}

 0 0

[Fe(H_{2}O)_{6}]^{2+}

 4 4.9

The Correct answer is option 4.

Posted by

Gautam harsolia

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