Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Medical
  • Match List - I with List - II List - I</stron

Match List - I with List - II

List - I List - II
(a)     [Fe(CN)_{6}]^{3-} (i) 5.92 BM

(b)    [Fe(H_{2}O)_{6}]^{3+}

 (ii) 0 BM
(c)    [Fe(CN)_{6}]^{4-} (iii) 4.90 BM
(d)    [Fe(H_{2}O)_{6}]^{2+} (iv) 1.73 BM

Choose the correct options from the given below:
 

Option: 1

(a) - (iv), (b) - (ii), (c)- (i), (d)- (iii)


Option: 2

(a) - (ii), (b) - (iv), (c)- (iii), (d)- (i)


Option: 3

(a) - (i), (b) - (iii), (c)- (iv), (d)- (ii)

 


Option: 4

(a) - (iv), (b) - (i), (c)- (ii), (d)- (iii)


Answers (1)

best_answer

CN^- is a strong field ligand and will cause pairing while H_2O is a weak field ligand and will not cause pairing

Thus, Fe^{3+} which has d^5 configuration and will have 1 unpaired electron in the complex with CN^- and 5 unpaired electrons in the complex with H_2O

And, Fe^{2+} which has d^6 configuration and will have 0 unpaired electron in the complex with CN^- and 4 unpaired electrons in the complex with H_2O

Complex unpaired electrons (n) Magnetic moment (BM)

[Fe(CN)_{6}]^{3-}

1

 1.73

[Fe(H_{2}O)_{6}]^{3+}

 5 5.92

[Fe(CN)_{6}]^{4-}

 0 0

[Fe(H_{2}O)_{6}]^{2+}

 4 4.9

The Correct answer is option 4.

Posted by

Gautam harsolia

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

Karnataka: NEET candidate dies by suicide; no note recovered
anam-khan

CBSE Re-evaluation Row: Dharmendra Pradhan seeks detailed report on technical failures
anam-khan

Before NEET, CMC Vellore’s unique MBBS admissions tested aptitude along with merit; paper-leak restarts debate

Latest Question