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Molar conductivities \left ( \wedge _{m}^{\circ } \right )at infinite dilution of NaCl, HCl \;and \;CH_3COONa \;are\; x, y\; and\; z respectively, \left ( \wedge _{m}^{\circ } \right ) for CH_3COOH will be

Option: 1

x + y + z
 


Option: 2

x + y - z


Option: 3

y + z - x

 


Option: 4

z + x -y


Answers (1)

best_answer

Answer (3)

\wedge _{CH_3COOH}^{\circ }=\wedge _{CH_3COONa}^{\circ }+\wedge _{HCl}^{\circ }-\wedge _{NaCl}^{\circ }

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chirag

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