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  • Mutual conductance of triode is and the amplification

Mutual conductance of triode is \mathrm{2\ m \Omega ^{-1}} and the amplification factor is \mathrm{50}. Its anode is connected with a source of \mathrm{250\ V} and a resistance of \mathrm{25\ k \Omega}. The voltage gain of this amplifier is

Option: 1

12.5


Option: 2

10


Option: 3

25


Option: 4

50


Answers (1)

best_answer

\begin{aligned} &\mathrm{ R_a=\frac{\mu}{\mathrm{g}_m}=\frac{50}{2 \times 10^{-3}}=25 \times 10^3 \Omega ;} \\ &\mathrm{ A_v=\frac{\mu R_L}{R_a+R_L}=\frac{50 \times 25 \times 10^3}{25 \times 10^3+25 \times 10^3}=25} \end{aligned}

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Rakesh

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