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  • n small metal drops of same size are charged 

n small metal drops of same size are charged  to 'V' volt each. If they coalesce to form a single large drop, then its potential will be -

Option: 1

\frac{V}{n}


Option: 2

Vn


Option: 3

Vn1/3


Option: 4

Vn2/3


Answers (1)

best_answer

Volume of 'n' small drops = Volume of Big drop

n\times \frac{4}{3}\Pi r^{3}= \frac{4}{3}\Pi R^{3}

n \times r^{3}= R^{3}

n^{1/3} \times r= R

Potential Vsmall = V =\frac{kq}{r}

= V_{big} =\frac{kQ}{R} = \frac{knq}{n^{1/3}r}

= V_{big} =\frac{kQ}{R} = \frac{kn^{1-1/3}q}{r} = n^{2/3}. V

= V_{big} = n^{2/3}. V

Posted by

manish

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