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  • Need explanation for: A man of 50 kg mass is standing in a gravity free space at a height of 10m above the floor. He throws a stone of 0.5kg mass downwards with a speed of 2m/s. When the stone reaches the floor, the distance of the man above the floo

A man of 50 kg mass is standing in a gravity free space at a height of 10m above the floor. He throws a stone of 0.5kg mass downwards with a speed of 2m/s. When the stone reaches the floor, the distance of the man above the floor will be:

  • Option 1)

    9.9m

  • Option 2)

    10.1m

  • Option 3)

    10m

  • Option 4)

    20m

 

Answers (1)

best_answer

As learnt in

Tips of distance -

Distance is a scalar quantity.

It is always positive.

S.I. Unit ightarrow meter (m).

Dimension left [ L ight ]

Distance is depend on path followed by body .

Distance geqslant Displacement.

- wherein

Displacement along circle is zero(0).

Semi circle

Distance=pi r

Displacement =2, r

 

 F_{ext}= 0     momentum remains conserved

\therefore 50u +0.5\times 2 = 0

where u - initial velocity of man

u = -\frac{1}{50}ms^{-1}     (negative sign shows that man moves upward)

Time taken by the stone

t = \frac{10}{2} = 5\ sec

\therefore  Distance moved by the man = 5 \times \frac{1}{50} = 0.1\ mt

\therefore   Distance of the man above floor = 10 + 0.1 = 10.1 mt


Option 1)

9.9m

This option is incorrect

Option 2)

10.1m

This option is correct

Option 3)

10m

This option is incorrect

Option 4)

20m

This option is incorrect

Posted by

divya.saini

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