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  • Nitrogen has the electronic configuration <img alt="1 s^{2}, 2 s^{2},2 p_{x}^{1}, 2 p_{y}^{1} ,2 p_{z}^{1}" src="/latex-image/?1%20s%5E%7B2%7D%2C%202%20s%5E%7B2%7D%2C2%20p_%7Bx%7D%5E%7B1%7D%2C

Nitrogen has the electronic configuration 1 s^{2}, 2 s^{2},2 p_{x}^{1}, 2 p_{y}^{1} ,2 p_{z}^{1} and not 1 s^{2}, 2 s^{2} ,2 p_{x}^{2}, 2 p_{y}^{1} ,2 p_{z}^{0} which is determined by

Option: 1

Aufbau's Principle


Option: 2

Pauli's exclusion principle


Option: 3

Hund's rule


Option: 4

Uncertainty Principle


Answers (1)

best_answer

The above is determined by Hund's rule of maximum multiplicity which says that pairing will not start until and unless all the degenerate orbitals are singly occupied first.

Posted by

vishal kumar

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