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  • on complete hydrolysis gives:Option: 1 <

\mathrm{XeF}_{6} on complete hydrolysis gives:

Option: 1

\mathrm{Xe}


Option: 2

\mathrm{XeO}_{2}


Option: 3

\mathrm{XeO}_{3}


Option: 4

\mathrm{XeO}_{2} \mathrm{~F}_{2}


Answers (1)

\mathrm{XeF}_{6}+3 \mathrm{H}_{2} \mathrm{O} \longrightarrow \mathrm{XeO}_{3}+6 \mathrm{HF}

Posted by

Sumit Saini

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