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  • One mole of anhydrous AB dissolves in water and liberates 20 J/mol of heat. The value of &nb

One mole of anhydrous AB dissolves in water and liberates 20 J/mol of heat. The value of \mathrm{\Delta_{hyd} H} = of AB is -30 J/mol. The heat of dissolution of hydrated (in KJ/mol) salt \mathrm{AB.2H_2O} is

Option: 1

-10


Option: 2

-50


Option: 3

10


Option: 4

-40


Answers (1)

best_answer

Dissolution of anhydrous salt AB

\mathrm{AB +aq + 2H_2O \rightarrow AB.2H_2O (aq) \;\;\;\; \Delta H_1 = -20J/mol}

Hydration of AB salt

\mathrm{AB + 2H_2O \rightarrow AB.2H_2O (s) \;\;\;\; \Delta H_2 = -30J/mol}

Subtracting 2nd equation from first we get


\mathrm{AB. 2H_2O(s) \rightarrow AB.2H_2O (aq) \;\;\;\; \Delta H_{hyd} = \Delta H_1 - \Delta H_2}

\mathrm{\Delta H_{hyd} =-20 + 30 = +10 J/mol}

Posted by

Deependra Verma

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