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  • One of the lines in the emission spectrum of  has the same wavelength as that of the 2nd line of Balmer series in hydrogen spect

One of the lines in the emission spectrum of Li^{2+} has the same wavelength as that of the 2nd line of Balmer series in hydrogen spectrum . The electronic transition corresponding to this line is n=12\rightarrow n=x. Find the value of x.

Option: 1

8


Option: 2

6


Option: 3

7


Option: 4

5


Answers (1)

best_answer

For 2nd line for Balmer series in hydrogen spectrum

\begin{aligned} & \frac{1}{\lambda}=\mathrm{R}(1)\left(\frac{1}{2^2}-\frac{1}{4^2}\right)=\frac{3}{16} \mathrm{R} \\ & \text { For } \mathrm{Li}^{2+}\left[\frac{1}{\lambda}=\mathrm{R} \times 9\left(\frac{1}{\mathrm{x}^2}-\frac{1}{12^2}\right)=\frac{3 \mathrm{R}}{16}\right] \end{aligned}

Which is satisfied by n=12\rightarrow n=6

Posted by

Deependra Verma

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