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Preeti reached the metro station and found that the escalator was not working. She walked up the stationary escalator in time  t_{1} . On other days, if she remains stationary on the moving escalator, then the escalator takes up in time t_{2}. The time taken by her to walk up on the moving escalator will be

Option: 1

\frac{{{t}_{1}}{{t}_{2}}}{{{t}_{2}}-{{t}_{1}}}


Option: 2

\frac{{{t}_{1}}{{t}_{2}}}{{{t}_{2}}+{{t}_{1}}}


Option: 3

{{t}_{1}}-{{t}_{2}}


Option: 4

\frac{{{t}_{1}}+{{t}_{2}}}{2}


Answers (1)

best_answer

Let v_{1} is the velocity of Preeti on a stationary escalator and d is the distance traveled by her.

\therefore {{v}_{1}}=\frac{d}{{{t}_{1}}}

Again, let {{v}_{2}} is the velocity of the escalator 

\therefore {{v}_{2}}=\frac{d}{{{t}_{2}}}

\therefore Net velocity of Preeti on moving escalator will be

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Riya

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