Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Medical
  • Projectile motion when projected horizontally with a speed of 20 m/s, Its angle made with the direction perpendicular to the ground  after  <img alt="t=2\sqr

Projectile motion when projected horizontally with a speed of 20 m/s, Its angle made with the direction perpendicular to the ground  after  t=2\sqrt{5} \ s is ?

Option: 1

{\mathrm{tan}}^{-1}\left(\frac{1}{\sqrt3}\right)


Option: 2

\ \tan^{-1}\sqrt5


Option: 3

\tan^{-1}\sqrt3


Option: 4

\tan^{-1}\left(\frac{1}{\sqrt5}\right)


Answers (1)

best_answer

Answer: (4)  \tan^{-1}\left(\frac{1}{\sqrt5}\right)

Explanation: 

tan\theta=\frac{v_x}{v_y}

Let,

     v_x=u   and      v_y=gt

    tan\theta\ =\frac{u}{gt}                                             

Or, \frac{20}{10\times2\sqrt5}                                           

Or,   tan\theta=\frac{1}{\sqrt5}                                

Or,   \theta\ =\ \tan^{-1}\left(\frac{1}{\sqrt5}\right)               

Posted by

avinash.dongre

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

NCAHP notifies UGC: NEET UG must for physiotherapy, university tests for psychology courses
anam-khan

Punjab NEET PG round 3 registration deadline extended to January 8 for MD, MS
anam-khan

NEET UG 2026 LIVE: NTA NEET syllabus out at neet.nta.nic.in; NEET brochure expected soon, updates

Latest Question