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A+2B+3C\rightleftharpoons AB_{2}C_{3}

Reaction of 6.0 g of A, 6.0\times1023 atoms of B, and 0.036 mol of C yields 4.8 g of compound AB2C3. If the atomic mass of A and C are 60 and 80 amu, respectively, the atomic mass of B is (Avogadro no.=6\times1023) :

Option: 1

70 amu


Option: 2

60 amu


Option: 3

50 amu


Option: 4

40 amu


Answers (1)

best_answer

As we have learnt, 

The chemical equation we have given is as follows:

A+2B+3C\rightleftharpoons AB_{2}C_{3}

We have given:

Atomic mass of A = 60 g/mol
Thus, moles of A = 6 / 60
                            = 0.1 moles

Now, Moles of C = 0.036 mol

Now, atome of B = 6.02 x 1023

Now, C is present in the leaast amount, thus C will be the limiting reagent.

Now, 3 moles of C will give 1 mol of AB2C3, thus 0.036 moles of C will give 0.012 moles of AB2C3

Now, we know that moles = given mass / molar mass

Therefore, molar mass of AB2C3 = (60 + 2x + 240)
x = 50 g/mol 

Thus atomic mass of B is 50 g/mol.

Therefore, Option(3) is correct

 

Posted by

himanshu.meshram

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