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  • represents the rate law for reaction beliuren A and B.

\mathrm{Rate =K[A]^m\left[B^n\right]} represents the rate law for reaction beliuren A and B.
If the concentration of A is increased three times but that of B is reduced to half.
Find the ratio of the new rate to the previous one.

Option: 1

\mathrm{2^{(n-m)}}


Option: 2

\mathrm{m+n}


Option: 3

\mathrm{\frac{3^m}{2^n}}


Option: 4

\mathrm{\frac{3^n}{2^m}}


Answers (1)

best_answer

\mathrm{\text { Earlier rate }=k[A]^m[B]^n}

\mathrm{\text { New rate }=k[3 A]^m[1 / 2 B]^n}

\mathrm{\text { Ratio }=3^m \times\left(\frac{1}{2}\right)^m=\frac{3^m}{2^n}}

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vinayak

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