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  • Stuck here, help me understand: Equal masses of H2, O2 and methane have been taken in a container of volume V attemperature 27oC in identical conditions. The ratio of the volumes of gases H2:O2:methane would be :

Equal masses of H2, O2 and methane have been taken in a container of volume V at temperature 27oC in identical conditions. The ratio of the volumes of gases H2:O2: methane would be :

  • Option 1)

    8 : 16 : 1

  • Option 2)

    16 : 8 : 1

  • Option 3)

    16: 1 : 2

  • Option 4)

    8 : 1 : 2

 

Answers (1)

best_answer

As learnt in

Partial Pressure of a gas in gaseous mixture -

Partial Pressure = (Total Pressure of Mixture) \times (mole fraction of gas)

 

-

 

 

Suppose mass is m

moles of H_{2} = m/2

moles of O_{2} = m/32

moles of methane = m/16

Volume ratio = \frac{m}{2}=\frac{m}{32}=\frac{m}{16}

= 16:1:2


Option 1)

8 : 16 : 1

This solution is incorrect.

Option 2)

16 : 8 : 1

This solution is incorrect.

Option 3)

16: 1 : 2

This solution is correct.

Option 4)

8 : 1 : 2

This solution is incorrect.

Posted by

Aadil

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